Выразить давление в паскалях гектопаскалях и килопаскалях

Задача №14.1 Физика 7 А.В.Пёрышкин

Дано:

${p}_{1}=5\,\text{гПа}$

${p}_{2}=0.02\,{\text{H/см}}^{2}$

${p}_{3}=0.4\,\text{кПа}$

${p}_{4}=10\,{\text{H/см}}^{2}$

${p}_{5}=10000\,\text{Па}$

${p}_{6}=5800\,\text{Па}$

${p}_{1}=?$

${p}_{2}=?$

${p}_{3}=?$

${p}_{4}=?$

${p}_{5}=?$

${p}_{6}=?$

Решение:

${p}_{1}=5\,\text{гПа}=500\,\text{Па}$

${p}_{2}=0.02\,{\text{H/см}}^{2}=200\,\text{Па}$

${p}_{3}=0.4\,\text{кПа}=400\,\text{Па}$

${p}_{4}=10\,{\text{H/см}}^{2}=100000\,\text{Па}$

${p}_{5}=10000\,\text{Па}=100\,\text{гПа}=10\,\text{кПа}$

${p}_{6}=5800\,\text{Па}=58\,\text{гПа}=5.8\,\text{кПа}$

Ответ:

${p}_{1}=500$ Па,

${p}_{2}=200$ Па,

${p}_{3}=400$ Па,

${p}_{4}=100000$ Па,

${p}_{5}=10$ кПа,

${p}_{6}=5.8$ кПа.