Задача №14.1 Физика 7 А.В.Пёрышкин
Дано:
\({p}_{1}=5\,\text{гПа}\)
\({p}_{2}=0.02\,{\text{H/см}}^{2}\)
\({p}_{3}=0.4\,\text{кПа}\)
\({p}_{4}=10\,{\text{H/см}}^{2}\)
\({p}_{5}=10000\,\text{Па}\)
\({p}_{6}=5800\,\text{Па}\)
\({p}_{1}=?\)
\({p}_{2}=?\)
\({p}_{3}=?\)
\({p}_{4}=?\)
\({p}_{5}=?\)
\({p}_{6}=?\)
Решение:
$${p}_{1}=5\,\text{гПа}=500\,\text{Па}$$
$${p}_{2}=0.02\,{\text{H/см}}^{2}=200\,\text{Па}$$
$${p}_{3}=0.4\,\text{кПа}=400\,\text{Па}$$
$${p}_{4}=10\,{\text{H/см}}^{2}=100000\,\text{Па}$$
$${p}_{5}=10000\,\text{Па}=100\,\text{гПа}=10\,\text{кПа}$$
$${p}_{6}=5800\,\text{Па}=58\,\text{гПа}=5.8\,\text{кПа}$$
Ответ: \({p}_{1}=500\) Па, \({p}_{2}=200\) Па, \({p}_{3}=400\) Па, \({p}_{4}=100000\) Па, \({p}_{5}=10\) кПа, \({p}_{6}=5.8\) кПа.